ANOVA and Paired T-test – GradSchoolPapers.com

Score:    Week 3    ANOVA and Paired T-testAt this point we know the following about male and female salaries.a.    Male and female overall average salaries are not equal in the population.b.    Male and female overall average compas are equal in the population, but males are a bit more spread out.c.    The male and female salary range are almost the same, as is their age and service.d.     Average performance ratings per gender are equal.Let’s look at some other factors that might influence pay – education(degree) and performance ratings.<1 point>    1    Last week, we found that average performance ratings do not differ between males and females in the population.Now we need to see if they differ among the grades. Is the average performace rating the same for all grades?(Assume variances are equal across the grades for this ANOVA.)                            You can use these columns to place grade Perf Ratings if desired.A    B    C    D    E    FNull Hypothesis:Alt. Hypothesis:Place  B17 in Outcome range box.Interpretation:What is the p-value:Is P-value < 0.05? Do we REJ or Not reject the null? If  the null hypothesis was rejected, what is the effect size value (eta squared): Meaning of effect size measure: What does that decision mean in terms of our equal pay question: <1 point>    2    While it appears that average salaries per each grade differ, we need to test this assumption.Is the average salary the same for each of the grade levels? (Assume equal variance, and use the analysis toolpak function ANOVA.)Use the input table to the right to list salaries under each grade level.Null Hypothesis:                            If desired, place salaries per grade in these columnsAlt. Hypothesis:                            A    B    C    D    E    FPlace  B55 in Outcome range box.What is the p-value:Is P-value < 0.05? Do you reject or not reject the null hypothesis: If  the null hypothesis was rejected, what is the effect size value (eta squared): Meaning of effect size measure: Interpretation: <1 point>    3    The table and analysis below demonstrate a 2-way ANOVA with replication.  Please interpret the results.BA    MA        Ho: Average compas by gender are equalMale    1.017    1.157        Ha: Average compas by gender are not equal0.870    0.979        Ho: Average compas are equal for each degree1.052    1.134        Ha: Average compas are not equal for each degree1.175    1.149        Ho: Interaction is not significant1.043    1.043        Ha: Interaction is significant1.074    1.1341.020    1.000        Perform analysis:0.903    1.1220.982    0.903        Anova: Two-Factor With Replication1.086    1.0521.075    1.140        SUMMARY    BA    MA    Total1.052    1.087        MaleFemale    1.096    1.050        Count    12    12    241.025    1.161        Sum    12.349    12.9    25.2491.000    1.096        Average    1.029083333    1.075    1.0520416670.956    1.000        Variance    0.006686447    0.006519818    0.0068660421.000    1.0411.043    1.043        Female1.043    1.119        Count    12    12    241.210    1.043        Sum    12.791    12.787    25.5781.187    1.000        Average    1.065916667    1.065583333    1.065751.043    0.956        Variance    0.006102447    0.004212811    0.0049334131.043    1.1291.145    1.149        TotalCount    24    24Sum    25.14    25.687Average    1.0475    1.070291667Variance    0.006470348    0.005156129ANOVASource of Variation    SS    df    MS    F    P-value    F critSample    0.002255021    1    0.002255021    0.383482117    0.538938951    4.06170646      (This is the row variable or gender.)Columns    0.006233521    1    0.006233521    1.060053961    0.308829563    4.06170646      (This is the column variable or Degree.)Interaction    0.006417188    1    0.006417188    1.091287766    0.301891506    4.06170646Within    0.25873675    44    0.005880381Total    0.273642479    47Interpretation:For Ho: Average compas by gender are equal                    Ha: Average compas by gender are not equalWhat is the p-value:Is P-value < 0.05? Do you reject or not reject the null hypothesis: If  the null hypothesis was rejected, what is the effect size value (eta squared): Meaning of effect size measure: For Ho: Average compas are equal for all degrees                      Ha: Average compas are not equal for all grades What is the p-value: Is P-value < 0.05? Do you reject or not reject the null hypothesis: If  the null hypothesis was rejected, what is the effect size value (eta squared): Meaning of effect size measure: For: Ho: Interaction is not significant            Ha: Interaction is significant What is the p-value: Is P-value < 0.05? Do you reject or not reject the null hypothesis: If  the null hypothesis was rejected, what is the effect size value (eta squared): Meaning of effect size measure: What do these decisions mean in terms of our equal pay question: Place data values in these columns <1 point>    4    Many companies consider the grade midpoint to be the “market rate” – what is needed to hire a new employee.                                            Salary    MidpointDoes the company, on average, pay its existing employees at or above the market rate?Null Hypothesis:Alt. Hypothesis:Statistical test to use:Place  the cursor in B160 for test.What is the p-value:Is P-value < 0.05? What else needs to be checked on a 1-tail in order to reject the null? Do we REJ or Not reject the null? If  the null hypothesis was rejected, what is the effect size value:            NA Meaning of effect size measure:    NA Interpretation: <2 points>    5.       Using the results up thru this week, what are your conclusions about gender equal pay for equal work at this point?
 
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